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School of Mathematics and Statistics
Carleton University
Math. 69.107
TEST 1 SOLUTIONS

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PART I: Multiple Choice Questions
(Choose and CIRCLE only ONE answer)
  1. [2 marks] Let tex2html_wrap_inline164 . Which of the following expressions represents the value of tex2html_wrap_inline166 ?
  2. (a) tex2html_wrap_inline168tex2html_wrap274 tex2html_wrap_inline170 , (c) tex2html_wrap_inline172 , (d) tex2html_wrap_inline174 .

  3. [2 marks] Let tex2html_wrap_inline176 . Then tex2html_wrap_inline178 is equal to:
  4. (a) tex2html_wrap_inline180 , (b) tex2html_wrap_inline182 , (c) tex2html_wrap_inline184tex2html_wrap276 tex2html_wrap_inline186 .

  5. [2 marks] Let y be given implicitly as a differentiable function of x by tex2html_wrap_inline190 . Then the slope of the tangent line of the curve y = y(x) at the point (x, y) where x=1, y=0 is equal to:
  6. tex2html_wrap278 tex2html_wrap_inline200 , (b) tex2html_wrap_inline202 , (c) tex2html_wrap_inline204 , (d) tex2html_wrap_inline206 .

  7. [2 marks] Evaluate the limit: tex2html_wrap_inline208
  8. (a) tex2html_wrap_inline202tex2html_wrap274 tex2html_wrap_inline200 , (c) The limit does not exist, (d) tex2html_wrap_inline214 .

  9. [2 marks] Answer TRUE or FALSE:
  10. If f is continuous at a point x=a in its domain, then f is differentiable at x=a.

    (a) TRUE, tex2html_wrap274 FALSE

PART II: Show all work here.
No additional pages will be accepted
  1. [5+5 marks] Find the required limits:
  2. a) tex2html_wrap_inline224 .

    b) tex2html_wrap_inline226

    Solution a) tex2html_wrap_inline228 or use L'Hospital's Rule directly after the second equation. So

    eqnarray81

    Solution b) The form of the limit is 0/0 so L'Hospital's Rule can be used. Thus, tex2html_wrap_inline232

  3. [5+5 marks] Evaluate the required derivative of each of the following functions:
  4. a) tex2html_wrap_inline234 . Find tex2html_wrap_inline236 .

    b) tex2html_wrap_inline238 . Find tex2html_wrap_inline240

    Solution a) tex2html_wrap_inline242

    At x=0, tex2html_wrap_inline246 and tex2html_wrap_inline248 , so tex2html_wrap_inline250 .

    Solution b) tex2html_wrap_inline252 .

    Next, we use the Product Rule:

    eqnarray119

  5. [10 marks] Find the equation of the tangent line to the curve tex2html_wrap_inline254 at the point x=2.
  6. Solution tex2html_wrap_inline258 . At x=2 the value is tex2html_wrap_inline262 . The equation of the tangent line is given by tex2html_wrap_inline264 where tex2html_wrap_inline266 and tex2html_wrap_inline268 . In other words, the equation looks like y - 1 = 24(x-2) or y = 24x -47.

Total: /40
 



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Angelo Mingarelli

Mon Oct 26 11:01:40 EST 1998