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School of Mathematics and Statistics
Carleton University
Math. 69.107
TEST 1 SOLUTIONS
Print Name:
Student Number:
PART I: Multiple Choice Questions
(Choose and CIRCLE only ONE answer)
-
[2 marks] Let
. Which of the following expressions represents the value of
?
(a)
,
, (c)
, (d)
.
-
[2 marks] Let
. Then
is equal to:
(a)
, (b)
, (c)
,
.
-
[2 marks] Let y be given implicitly as a differentiable function
of x by
. Then the slope of the tangent line of the curve y = y(x)
at the point (x, y) where x=1, y=0 is equal
to:
, (b)
, (c)
, (d)
.
-
[2 marks] Evaluate the limit:
(a)
,
, (c) The limit does not exist, (d)
.
-
[2 marks] Answer TRUE or FALSE:
If f is continuous at a point x=a in its domain,
then f is differentiable at x=a.
(a) TRUE,
FALSE
PART II: Show all work here.
No additional pages will be accepted
-
[5+5 marks] Find the required limits:
a)
.
b)
Solution a)
or use L'Hospital's Rule directly after the second equation. So
Solution b) The form of the limit is 0/0 so L'Hospital's Rule
can be used. Thus,
-
[5+5 marks] Evaluate the required derivative of each of the following
functions:
a)
. Find
.
b)
. Find
Solution a)
At x=0,
and
, so
.
Solution b)
.
Next, we use the Product Rule:
-
[10 marks] Find the equation of the tangent line to the curve
at the point x=2.
Solution
. At x=2 the value is
. The equation of the tangent line is given by
where
and
. In other words, the equation looks like y - 1 = 24(x-2)
or y = 24x -47.
Total: /40
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Angelo Mingarelli
Mon Oct 26 11:01:40 EST 1998